WebTrimEnd is a function that returns the changed value. You aren't actually assigning the trimmed string value (back to a variable) in your code as-is. Change your code to: NFPAFPRACHGLOES = … WebAug 23, 2012 · String.TrimEnd is the answer — trims selected characters from the end of the string only. Note: You should pay attention to the documentation in MSDN: there was a breaking change to the behavior of this method, so the actual behavior depends on the version of .NET Framework you are targetting: Notes to Callers
Remove last specific character in a string c# - Stack …
WebApr 11, 2024 · Finally, I trim any / character from the end since variants with and without a trailing / would still be the same URL. To identify integers and GUIDs inside the path of the URL, we could use regular expressions or write an ugly foreach loop. But luckily, being C# developers we have LINQ to easily write code like this: WebFeb 6, 2012 · To trim any of the characters in trimChars from the start/end of target (e.g. "foobar'@"@';".TrimEnd (";@'") will return "foobar") you can use the following: TrimStart public static string TrimStart (this string target, string trimChars) { return target.TrimStart (trimChars.ToCharArray ()); } TrimEnd theanglo.mx
how to remove a character at the end of a string in linq c#
WebWhile trimming ANY combination of characters that make up a new line char (s) does address underlying problem and the spirit of the question, it also leaves a potential for unwanted functionality in the general sense. WebJun 27, 2024 · You are using linq to sql and database does not understand TrimEnd or Trim. So first you have need to load data in memory and then use TrimEnd method. var hatoList = (from L in db.vHatoList select L.HatoFullName).ToList (). Select (t=>t.TrimEnd ('.')); Share Improve this answer Follow edited Jun 27, 2024 at 7:15 answered Jun 27, … WebMay 22, 2024 · If you want to use the more general form of trimEnd (), that is to remove an arbitrary set of trailing characters then you need to modify it slightly to use: "string".replaceAll (" [" + characters + "]+$", ""); the anglo-irish treaty of 1922